NABOKV-L post 0014209, Tue, 28 Nov 2006 16:28:19 -0500

Subject
Re: "C" "K" "S" in PF solution
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Date
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I would expand Carolyn's Cabbalistic Equation:

C = K = S = Z (Z for Zembla) - since in Russian usage following German
or Dutch prononciation of S, many Germanic words that start with S are
transiterated with 3 (=Z) in Cyrillic, for example Brechtian term "Song"
became known as a "zong". And we recall that Zembla is Semberland.

Adding Cyrillic 3, we get also Pythagorean triad, the number of main
characters in PF.

C = K = S = 3 = Z

And then C = K = S = 3 = Z = C since Germanic Z is pronounced "ts", so
one goes a full zirkle.

I have to run to class otherwise "I could talk like this forever" (HMS
Pinafore)...

Victor Fet

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